(5-i)z^2+2iz+i=0

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Solution for (5-i)z^2+2iz+i=0 equation:


Simplifying
(5 + -1i) * z2 + 2iz + i = 0

Reorder the terms for easier multiplication:
z2(5 + -1i) + 2iz + i = 0
(5 * z2 + -1i * z2) + 2iz + i = 0

Reorder the terms:
(-1iz2 + 5z2) + 2iz + i = 0
(-1iz2 + 5z2) + 2iz + i = 0

Reorder the terms:
i + 2iz + -1iz2 + 5z2 = 0

Solving
i + 2iz + -1iz2 + 5z2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-5z2' to each side of the equation.
i + 2iz + -1iz2 + 5z2 + -5z2 = 0 + -5z2

Combine like terms: 5z2 + -5z2 = 0
i + 2iz + -1iz2 + 0 = 0 + -5z2
i + 2iz + -1iz2 = 0 + -5z2
Remove the zero:
i + 2iz + -1iz2 = -5z2

Combine like terms: -5z2 + 5z2 = 0
i + 2iz + -1iz2 + 5z2 = 0

The solution to this equation could not be determined.

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